9q^2+14=Q

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Solution for 9q^2+14=Q equation: 



9q^2+14=

We move all terms to the left:

9q^2+14-()=0

We add all the numbers together, and all the variables

9q^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{0}{18}=0$

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